Tuesday, 19 May 2020

C++ compiler setup on windows os machine

Step 1) Install mingw64 compiler

There are two ways to install this compiler.
A) Download mingw64 installer from http://mingw-w64.org/doku.php/download . Select MingW-W64-builds 
It will download installer, and run that file. Chose correct settings during setup like 32bit/64bit configuration.

B) If you are facing any issue with type A, then one can directly download mingw64.7z file.
Once downloaded, extract the .7z file onto your PC using 7-zip and extract to a folder such as C:\MinGW64.

You don't have to put it in 'Program Files' like the installer does.

Step 2) Once installation is over then set windows path.
Open control panel, search "env", select edit system settings. Now, under system variables
select "path" and select edit option. Now, add new entry "C:\<path to mingw64>\bin" and move it up little bit, and just below system32 paths.
Click ok to all.

Step 3) Check if C++ compiler installation is successful
Now, open terminal, and run "g++ --version". If you see mingw related info then installation is success.

Note: if you still have trouble downloading the compiler, click on the 'Problems Downloading?' button on the next screen so you can try to download it from different site around the world.

============================================================
Codelite IDE setup

Download Codelite IDE from: https://codelite.org/

Open codelite IDE, select "Run the setup wizard" under "help" section. Map/scan for already installed c++ compiler "mingw64" and setup this path.

Create workspace with C++ type.

Create Project with below options:
  Category: console
  Type: Simple executable (g++)
  Compiler: Mingw
  Debugger: GNU gdb debugger
  Build system: Default

Update project configuration as
Linker option : -static
Compiler options (add): -Wall; -std=c++17;
--------------------------------------------------------------------
To build & Run: Select "Run" under "build" section
===============================================================

Friday, 7 September 2018

Program to demonstrate using O_DIRECT option in file operations and writev() call

Program

/* Below program showcases the use of O_DIRECT file option. Also, demonstrates writev() use */

#include <iostream>
#include <fcntl.h>    /* For O_RDWR */
#include <unistd.h>   /* For open(), creat() */
#include <string.h>   /* For strlen() */
#include <malloc.h>   /* For memalign() */
#include <sys/uio.h>  /* For struct iovec */
#include <stdint.h>   /* For datatypes */

#define O_DIRECT_ENABLE 1
using namespace std;

int main(int argc, char *argv[])
{
        if (argc != 3) {
            cout << "run: ./<prog_binary_name> <input_file_name> <outputFileName>"<<endl;
            return 0;
        }

        int fd_out, fd_in, ret;
#if O_DIRECT_ENABLE
        fd_out = open(argv[2], O_CREAT | O_WRONLY | O_TRUNC | O_APPEND | O_DIRECT, S_IRWXG | S_IRWXU);
        fd_in = open(argv[1], O_RDONLY | O_DIRECT);
#else
        fd_out = open(argv[2], O_CREAT | O_WRONLY | O_TRUNC | O_APPEND, S_IRWXG | S_IRWXU);
        fd_in = open(argv[1], O_RDONLY);
#endif
        if(!fd_out || !fd_in) {
            cout << "Unable to open one of the given files"<<endl;
            return 0;
        }
        char file_data1[4096];
        char *file_data2 = (char*)memalign(4096, 4096);

        /* Below vector declaration won't compile since aligned_allocator defined in xilinx lib.
        vector<uint8_t, aligned_allocator<uint8_t>>  file_data3(4096);
        read(fd_in, file_data3, 4096);
        int file_data3_len = strlen(file_data2);
        */

        read(fd_in, file_data1, 4096); /* not work with O_DIRECT option, it returns 0 bytes */
        int file_data1_len = strlen(file_data1);

        /* works with O_DIRECT since memalign is used for creating the buffer */
        read(fd_in, file_data2, 4096);
        int file_data2_len = strlen(file_data2);

        cout<<"read_4k_nonMemAlign, read_4k_memAlign: "<<file_data1_len<<", "<<file_data2_len<<endl;

        char *data = (char*)malloc(sizeof(char)* 4096);
        strcpy(data, "salkfalksfjslfnsdlfksdklfnsldkfslkdfskldfjskldngslkdgjsdngslkdgskldglksdglksdglsdglsdgklsdfgdfkg");
        int data_len =  strlen(data);

        char *data2 = (char*)memalign(4096, 4096);
        strcpy(data2, "12345678912345678912345678912345678912345678912345678912345678912345678912345678912345678912345");
        int data2_len =  strlen(data2);

        ret = write(fd_out, data, data_len); /* fails with -1 if O_DIRECT enabled */
        cout<<"data(malloc) write ret: "<<ret<<endl;

        ret = write(fd_out, data2, 4096); /* write() works with O_DIRECT since data buffer is memaligned and given size is 4096 also aligned */
        cout<<"data2(memalign) write ret: "<<ret<<endl;

        ret = lseek(fd_out, data_len, SEEK_SET);
        cout<<"seek ret1: "<<ret<<endl;
        ret = write(fd_out, file_data2, 4096); /* write() works with O_DIRECT since buf is memaligned */
        cout<<"write_ret2: "<<ret<<endl;

        ret = lseek(fd_out, 0, SEEK_CUR);
        cout<<"seek ret2: "<<ret<<endl;

        struct iovec    iov[4];
        iov[0].iov_base = (char *) file_data2;
        iov[0].iov_len  = 4096;
        iov[1].iov_base = (char *) data2;
        iov[1].iov_len  = 4096;//data2_len;
        iov[2].iov_base = (char *) file_data1;
        iov[2].iov_len  = file_data1_len;
        iov[3].iov_base = (char *) data;
        iov[3].iov_len  = data_len;

        int total_len = iov[0].iov_len + iov[1].iov_len + iov[2].iov_len + iov[3].iov_len;
        cout<<"total_len: "<<total_len<<" {"<<data_len<<", "<<data2_len<<", "<<file_data1_len<<", "<<file_data2_len<<"}"<<endl;

/*        ret = writev(fd_out, &iov[0], 4); */
        ret = writev(fd_out, &iov[0], 2);
        cout<<"writev ret: "<<ret<<endl; /*writev() works fine when O_DIRECT flag removed in file open option. */
        ret = lseek(fd_out, 4096+data2_len, SEEK_SET);
        cout<<"seek ret: "<<ret<<endl;
        ret = write(fd_out, data, 4096); /* write() works with O_DIRECT since buf is memaligned */
        cout<<"ret: "<<ret<<endl;
        close(fd_out);
        close(fd_in);
        return 0;
}

Program Output

$g++ odirect_writev_prog.cpp -o odirect_writev_prog
$ ./odirect_writev_prog input.txt output_fd.txt
read_4k_nonMemAlign, read_4k_memAlign: 0, 4096
data(malloc) write ret: -1
data2(memalign) write ret: 4096
seek ret1: 96
write_ret2: -1
seek ret2: 96
total_len: 8288 {96, 95, 0, 4096}
writev ret: -1
seek ret: 4191
ret: -1

Tuesday, 31 October 2017

Generate Binary Numbers using Queue data structure

Generate Binary Numbers using Queue data structure

Problem Statement (from geeksforgeeks):

Given a number n, Write a program that generates and prints all binary numbers with decimal values from 1 to n.
Input:
The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N.

Output:
Print all binary numbers with decimal values from 1 to n in a single line.

Constraints:
1 ≤ T ≤ 100
1 ≤ N ≤ 500

Example:
Input
2
2
5
Output
1 10
1 10 11 100 101

Solution:

/* Generating Binary Numbers of given input using Queue Data structure.
 * Implemented in C language.
 * Used Circular Queue as part of the implementation
 */

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

struct queue{
    int cap;
    int front, rear;
    int size;
    char array[1000][10];
};

struct queue* createQueue(int n){
    struct queue *q = (struct queue*)malloc(sizeof(struct queue));
    
    q->cap = n;
    q->front = -1;
    q->rear = n - 1;
    q->size = 0;
    return q;
}

int isQueueEmpty(struct queue *q){
    return q->size == 0;
}

int isQueueFull(struct queue *q){
    return q->size == q->cap;
}

void enQueue(struct queue *q, char *ch){
    if (isQueueFull(q))
        return;
    q->rear = (q->rear + 1) % q->cap;
    strcpy (q->array[q->rear], ch);
    q->size += 1;
}

char* deQueue(struct queue *q){
    if (isQueueEmpty(q))
        return NULL;
    q->front = (q->front + 1) % q->cap;
    q->size -= 1;
    return q->array[q->front];
    
}

void printQueue(struct queue *q){
    printf("Queue elements...\n");
    for (int i = 0; i < q->front; i++)
        printf("ele: %s\n", q->array[i]);
}
void toBinary(int n) {
    struct queue *q = createQueue(n);
    
    enQueue(q, "1");
    
    for (int i = 1; i <= n; i++) {
        char d1[10], d2[10];
        strcpy(d1, deQueue(q));
        printf("%s ", d1);
        strcpy(d2, d1);
        strcat(d1, "0");
        strcat(d2, "1");
        enQueue(q, d1);
        enQueue(q, d2);
    }
    printf("\n");
    free(q);
}

int main()
{
    // Note that size of arr[] is considered 100 according to
    // the constraints mentioned in problem statement.
    int arr[100], t, n;
 
    // Input the number of test cases you want to run
    scanf("%d", &t); 
 
    // One by one run for all input test cases
    while (t--)
    {
        // Input the size of the array
        scanf("%d", &n);
        toBinary(n);
    }
    return 0;
}

Friday, 2 September 2016

Python Learning - Notes


I have prepared this document during my Python course from sololearn.com

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